Question:
The clinical trial phase I, 60% of patients respond to Drug A, 50% of patients respond to Drug B, and 20% of patients respond to both Drug A and Drug B. how many randomly patients can response the drug
The clinical trial phase I, 60% of patients respond to Drug A, 50% of patients respond to Drug B, and 20% of patients respond to both Drug A and Drug B. how many randomly patients can response the drug
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Total = A + B - Both. Simple Venn diagram logic.
Updated On: May 25, 2026
- 0.1000000000000001
- 0.9
- 0.5
- Not defined
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The Correct Option is B
Solution and Explanation
Step 1: Concept
This is a probability problem using the Addition Rule: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.
Step 2: Meaning
We want to find the probability that a patient responds to *at least one* of the drugs (Drug A or Drug B).
Step 3: Analysis
Given: $P(A) = 0.60$, $P(B) = 0.50$, and $P(A \cap B) = 0.20$. Calculation: $0.60 + 0.50 - 0.20 = 0.90$.
Step 4: Conclusion
The probability of a response to either drug is 0.9. Final Answer: (B)
This is a probability problem using the Addition Rule: $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.
Step 2: Meaning
We want to find the probability that a patient responds to *at least one* of the drugs (Drug A or Drug B).
Step 3: Analysis
Given: $P(A) = 0.60$, $P(B) = 0.50$, and $P(A \cap B) = 0.20$. Calculation: $0.60 + 0.50 - 0.20 = 0.90$.
Step 4: Conclusion
The probability of a response to either drug is 0.9. Final Answer: (B)
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