Question

Write the IUPAC name of the given compound: $CH_3CH(CH_3)CH(Br)CH_3$

Hint:

Always arrange substituent prefixes alphabetically (Bromo before Methyl) and assign the lowest possible numbers.

Answer 1

Step 1: Concept
IUPAC nomenclature rules for branched haloalkanes.

Step 2: Meaning
Identify the longest continuous carbon chain and number it to give the substituents the lowest possible locants.

Step 3: Analysis
The longest carbon chain contains 4 carbon atoms (butane).
Numbering from the right side gives the bromo group the position 2 and the methyl group the position 3.
Numbering from the left would give methyl position 2 and bromo position 3. Alphabetical priority dictates
that Bromo gets precedence for the lower number when possible, making 2-bromo-3-methylbutane the correct designation.

Step 4: Conclusion
Combining the substituents alphabetically gives the final IUPAC name.

Final Answer: 2-Bromo-3-methylbutane