A hydrocarbon C5H10 does not react with chlorine in the dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.
A hydrocarbon with the molecular formula, C5H10 belongs to the group with a general molecular formula CnH2n. Therefore, it may either be an alkene or a cycloalkane. Since hydrocarbon does not react with chlorine in the dark, it cannot be an alkene. Thus, it should be a cycloalkane. Further, the hydrocarbon gives a single monochloro compound, C5H9Cl by reacting with chlorine in bright sunlight. Since a single monochloride mixture is formed, the hydrocarbon must contain all equivalent H-atoms. Also, as all H−atoms of a cycloalkane are identical, the hydrocarbon must be a cycloalkane. Hence, the said compound is cyclopentane.

The reactions involved in the question are:

Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Give the IUPAC names of the following compounds:
(i)CH3CH(Cl)CH(Br)CH3
(ii)CHF2CBrClF
(iii)ClCH2C≡CCH2Br
(iv)(CCl3)3CCl
(v)CH3C(p-ClC6H4)2CH(Br)CH3
(vi)(CH3)3CCH=CClC6H4I-p
Write the structures of the following organic halogen compounds.
(i) 2-Chloro-3-methylpentane
(ii)p-Bromochlorobenzene
(iii)1-Chloro-4-ethylcyclohexane
(iv)2-(2-Chlorophenyl)-1-iodooctane
(v)2-Bromobutane
(vi)4-tert-Butyl-3-iodoheptane
(vii)1-Bromo-4-sec-butyl-2-methylbenzene
(viii)1,4-Dibromobut-2-ene
Which one of the following has the highest dipole moment?
(i)CH2Cl2
(ii)CHCl3
(iii)CCl4
Write the isomers of the compound having formula C4H9Br.