Which one of the following has the highest dipole moment?
(i)CH2Cl2
(ii)CHCl3
(iii)CCl4
CH2Cl2
CHCl3
CCl4
(i)
Dichlormethane(CH2Cl2) µ=1.60D
(ii) 
Chloroform(CHCl3) µ=1.08D
(iii) 
Carbon tetrachloride(CCl4)
µ=0D CCl4 is a symmetrical molecule. Therefore, the dipole moments of all four C−Cl bonds cancel each other. Hence, its resultant dipole moment is zero. As shown in the above figure, in CHCl3, the resultant dipole moments of two C−Cl bonds are opposed by the resultant dipole moments of one C−H bond and one C−Cl bond. Since the resultant of one C−H bond and one C−Cl bond dipole moment is smaller than two C−Cl bonds, the opposition is to a small extent. As a result,CHCl3 has a small dipole moment of 1.08 D. the other hand, in the case of CH2Cl2, the resultant of the dipole moments of two C−Cl bonds is strengthened by the resultant of the dipole moments of two C−H bonds. As a result, CH2Cl2 has a higher dipole moment of 1.60 D than CHCl3 i.e.,CH2Cl2 has the highest dipole moment. Hence, the given compounds can be arranged in the increasing order of their dipole moments as CCl4<CHCl3<CH2Cl2.
Give two differences between N1 and N2 reactions.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).