Which element is a strong reducing agent in +2 oxidation state and why?
The element that acts as a strong reducing agent in its +2 oxidation state is Zinc (Zn).
Zinc has a relatively low standard electrode potential:
\( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
This negative value indicates that metallic zinc readily loses electrons to form \( \text{Zn}^{2+} \) ions:
\( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)
The more negative the \( E^\circ \) value, the stronger the reducing power, as it reflects a higher tendency to donate electrons.
Thus, in the +2 oxidation state, zinc acts as a strong reducing agent and is capable of reducing other chemical species by donating electrons.
Convert Propanoic acid to Ethane
Acidified \(KMnO_4\) oxidizes sulphite to:
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).