Convert Propanoic acid to Ethane
To convert propanoic acid to ethane, we perform a reduction reaction using a strong reducing agent like LiAlH.
The steps are: 1. Reduction of Propanoic acid: Propanoic acid is reduced by lithium aluminum hydride (LiAlH) to ethanol. \[ \text{CH}_3\text{CH}_2\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{CH}_3\text{CH}_2\text{OH} \] 2. Reduction of Ethanol to Ethane: Ethanol is then reduced further by a reducing agent like zinc in the presence of hydrochloric acid (Zn/HCl) to ethane. \[ \text{CH}_3\text{CH}_2\text{OH} \xrightarrow{\text{Zn/HCl}} \text{CH}_3\text{CH}_3 \] Thus, Propanoic acid is first converted to ethanol and then ethanol to ethane.
Acidified \(KMnO_4\) oxidizes sulphite to:
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).