Question:

The IUPAC name of the following compound is:

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In cyclic alkenes, numbering always starts from the double bond to give it lowest locant priority.
Updated On: Jun 20, 2026
  • 1-Bromo-2-methyl-3-chlorocyclohex-2-ene
  • 1-Bromo-3-chloro-2-methylcyclohex-2-ene
  • 3-Bromo-1-chloro-2-methylcyclohex-1-ene
  • 3-Bromo-2-methyl-1-chlorocyclohex-1-ene
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The Correct Option is C

Solution and Explanation

Step 1: Identify the parent structure.
The compound is a cyclohexene derivative, meaning the parent chain is a six-membered ring containing one double bond. The double bond gets highest priority in numbering.

Step 2: Assign numbering of ring.

Numbering starts from the double bond to give it the lowest possible locant (cyclohex-1-ene). After fixing the double bond positions, substituents are assigned numbers to give lowest set of locants.

Step 3: Identify substituents.

The substituents present are: - Bromo group - Chloro group - Methyl group We assign numbers such that the substituents get the lowest possible positions while maintaining double bond at position 1.

Step 4: Apply IUPAC priority rules.

Alphabetical order is used while writing substituents: bromo, chloro, methyl. After correct numbering, positions become: - 3-bromo - 1-chloro - 2-methyl

Step 5: Construct final name.

Combining substituent positions with parent chain name gives: cyclohex-1-ene backbone with substituents at positions 3,1,2 respectively.

Step 6: Final verification.

The correct systematic IUPAC name is: 3-Bromo-1-chloro-2-methylcyclohex-1-ene.
Final Answer: \[ \boxed{\text{3-Bromo-1-chloro-2-methylcyclohex-1-ene}} \]
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