Question:
Identify the product P
to give product P
Identify the product P
to give product P
to give product P
Show Hint
Grignard reagents react with CdCl\(_2\) to form dialkyl cadmium compounds via transmetallation.
Updated On: Jun 20, 2026
- \((\text{Ph-CH}_2)_2\text{Cd}\)
- Ph-CH\(_2\)-Cd
- Ph-CH\(_2\)-Cl
- Ph-CH\(_2\)-CH\(_2\)-Ph
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Formation of Grignard reagent.
Benzyl bromide (Ph-CH\(_2\)-Br) reacts with Mg in dry ether to form benzyl magnesium bromide: \[ \text{Ph-CH}_2\text{-Br} + Mg \rightarrow \text{Ph-CH}_2\text{-MgBr} \] This is a Grignard reagent, which is highly reactive nucleophilic organomagnesium compound.
Step 2: Reaction with CdCl\(_2\).
Grignard reagent reacts with cadmium chloride (CdCl\(_2\)) in a transmetallation reaction. In this process, MgBr group is replaced by Cd to form organocadmium compound.
Step 3: Formation of dialkyl cadmium compound.
Since Cd is divalent, it bonds with two benzyl groups: \[ 2 \, \text{Ph-CH}_2\text{-MgBr} + CdCl_2 \rightarrow (\text{Ph-CH}_2)_2Cd + 2MgBrCl \]
Step 4: Identify product structure.
The final product is dialkyl cadmium compound where two benzyl groups are attached to Cd: \[ (\text{Ph-CH}_2)_2Cd \]
Step 5: Reaction type understanding.
This is a classic organometallic exchange (transmetallation) where Grignard reagents convert into less reactive organocadmium compounds used in controlled synthesis.
Step 6: Final conclusion.
Thus, product P is benzyl cadmium compound with two benzyl groups attached to Cd.
Final Answer: \[ \boxed{(\text{Ph-CH}_2)_2Cd} \]
Benzyl bromide (Ph-CH\(_2\)-Br) reacts with Mg in dry ether to form benzyl magnesium bromide: \[ \text{Ph-CH}_2\text{-Br} + Mg \rightarrow \text{Ph-CH}_2\text{-MgBr} \] This is a Grignard reagent, which is highly reactive nucleophilic organomagnesium compound.
Step 2: Reaction with CdCl\(_2\).
Grignard reagent reacts with cadmium chloride (CdCl\(_2\)) in a transmetallation reaction. In this process, MgBr group is replaced by Cd to form organocadmium compound.
Step 3: Formation of dialkyl cadmium compound.
Since Cd is divalent, it bonds with two benzyl groups: \[ 2 \, \text{Ph-CH}_2\text{-MgBr} + CdCl_2 \rightarrow (\text{Ph-CH}_2)_2Cd + 2MgBrCl \]
Step 4: Identify product structure.
The final product is dialkyl cadmium compound where two benzyl groups are attached to Cd: \[ (\text{Ph-CH}_2)_2Cd \]
Step 5: Reaction type understanding.
This is a classic organometallic exchange (transmetallation) where Grignard reagents convert into less reactive organocadmium compounds used in controlled synthesis.
Step 6: Final conclusion.
Thus, product P is benzyl cadmium compound with two benzyl groups attached to Cd.
Final Answer: \[ \boxed{(\text{Ph-CH}_2)_2Cd} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Hydrocarbons Questions
- Among the following the correct statements are:
I. Carbon black is obtained by burning hydrocarbons in a limited supply of air
II. Carbon black is obtained by burning hydrocarbons in absence of air
III. Coke is obtained by burning coal at high temperatures in a limited supply of air
IV. Coke is obtained by burning coal at high temperatures in absence of air - A halide with formula C6H13Br gave two isomeric alkenes A and B on dehydrobromination. On ozonolysis of mixture of A and B the following compounds were obtained: CH3COCH3, CH3CHO, CH3CH2CHO and (CH3)2CHCHO. The halide is:
- One mol of 2-Methylbuta-1,3-diene on ozonolysis gives
- Chloroform in the presence of light is slowly oxidized by air to form
- Identify the major product
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions