Question:
Identify the major product formed when 3-bromo-2-cyclohexene is treated with alcoholic KOH.
Identify the major product formed when 3-bromo-2-cyclohexene is treated with alcoholic KOH.
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Whenever possible, elimination reactions in cyclic systems may proceed toward aromatic stabilization.
Updated On: Jun 19, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Understanding reagent behavior.
Alcoholic KOH acts as a strong base and favors elimination (E2 reaction) over substitution, leading to removal of HBr.
Step 2: Identifying elimination process.
In 3-bromo-2-cyclohexene, removal of HBr leads to formation of additional double bond, increasing unsaturation in the ring.
Step 3: Aromatization possibility.
After elimination, the system undergoes dehydrogenation leading to complete conjugation in the ring, forming an aromatic benzene structure. Aromaticity provides extra stability.
Step 4: Stability factor.
Formation of benzene is highly favored due to aromatic stabilization energy, making it the major product.
Step 5: Final conclusion.
Thus, the reaction results in aromatization to benzene as the major product.
Final Answer: \[ \boxed{\text{Benzene}} \]
Alcoholic KOH acts as a strong base and favors elimination (E2 reaction) over substitution, leading to removal of HBr.
Step 2: Identifying elimination process.
In 3-bromo-2-cyclohexene, removal of HBr leads to formation of additional double bond, increasing unsaturation in the ring.
Step 3: Aromatization possibility.
After elimination, the system undergoes dehydrogenation leading to complete conjugation in the ring, forming an aromatic benzene structure. Aromaticity provides extra stability.
Step 4: Stability factor.
Formation of benzene is highly favored due to aromatic stabilization energy, making it the major product.
Step 5: Final conclusion.
Thus, the reaction results in aromatization to benzene as the major product.
Final Answer: \[ \boxed{\text{Benzene}} \]
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