(1): Thermal Decomposition of Potassium Permanganate (KMnO4)
- On heating, potassium permanganate (KMnO4) decomposes to form potassium manganate (K2MnO4), manganese dioxide (MnO2), and oxygen gas (O2).
- This reaction is used in laboratories as a source of oxygen.
The thermal decomposition reaction is:
2KMnO4 heat → K2MnO4 + MnO2 + O2
(2): Redox Reaction of Dichromate and Iodide in Acidic Medium
- Dichromate (Cr2O72−) acts as an oxidizing agent and oxidizes iodide (I−) to iodine (I2) in acidic medium.
- The chromium in dichromate is reduced from Cr6+ to Cr3+.
- The reaction follows the principles of redox balancing, maintaining charge and mass balance.
The balanced redox reaction is:
Cr2O72− + 6I− + 14H+ → 2Cr3+ + 3I2 + 7H2O
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Calculate \( \Lambda_m^0 \) for acetic acid and its degree of dissociation (\( \alpha \)) if its molar conductivity is 48.1 \( \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \).
Given that
\( \Lambda_m^0 (\text{HC}) = 426 \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \),
\( \Lambda_m^0 (\text{NaCl}) = 126 \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \),
\( \Lambda_m^0 (\text{CH}_3\text{COONa}) = 91 \, \Omega^{-1} \, \text{cm}^2 \, \text{mol}^{-1} \).