List of top Questions asked in MHT CET- 2025

An electric dipole of length \(2 \text{ cm}\) is placed at \(60^{\circ}\) to a uniform electric field of \(10^{5} \text{ N/C}\). If it experiences a torque of \(9\sqrt{3} \text{ Nm}\), the magnitude of the charge is:
A (2.5 V) battery is connected to a potentiometer wire. A cell of e.m.f. (1.08 V) is balanced by the voltage drop across (2.16 m) of wire. The length of the potentiometer wire is
Two inductors of \(80 \text{ mH}\) each are joined in parallel. If the current is \(2.1 \text{ A}\), the energy stored in the combination is
A photosensitive surface has work function (\phi). If photon of energy (3\phi) falls on this surface, the electron comes out with maximum velocity of (4 \times 10^6 m/s). When photon energy is increased to (7\phi) then maximum velocity will be
The liquid (mercury) meniscus in capillary tube will be convex if the angle of contact is
A beam of light of intensity \(I_0\) falls on a system of three polaroids such that each pass axis is turned through \(60^{\circ}\) with respect to preceding one. The fraction of intensity that passes through is:
The angular momentum of a rotating body is '\(L\)'. When frequency is tripled and kinetic energy is made one-third, the new angular momentum becomes
A person observes two moving trains. First reaching the station and another leaves the station with equal speed of \(30 \text{ m/s}\). If both trains emit sounds of frequency \(300 \text{ Hz}\), difference of frequencies heard by the person will be (speed of sound in air \(330 \text{ m/s}\))
An open organ pipe and closed organ pipe of same length produce \(2\) beats per second in fundamental mode. The length of open pipe is made half and that of closed pipe is doubled. The number of beats produced per second will be:
The value of alternating e.m.f. (\(E\)) in the given circuit is
The electric flux through the surface
In an \(LC\) circuit, angular frequency at resonance is \(\omega\). The new angular frequency when inductance is made four times and capacitance is made eight times is
A student studies for (X) number of hours during a randomly selected school day. The probability that (X) can take the values, has the following form, where (k) is some constant.
(P(X = x) = 0.2, & if x = 0
kx, & if x = 1 or 2
k(6 - x), & if x = 3 or 4
0, & otherwise )
The probability that the student studies for at most two hours is
The value of (\tan [2 \tan^{-1} \frac{1}{5} - \frac{\pi}{4}]) is
In a triangle (ABC), with usual notations, the sides (a, b, c) are such that they are roots of the equation (x^3 - 11x^2 + 38x - 40 = 0) then (\frac{\cos A}{a} + \frac{\cos B}{b} + \frac{\cos C}{c} = )
The general solutions of the equation (\tan^2 \theta + \sec 2\theta = 1) are
If $\vec{a} = \frac{1}{\sqrt{10}}(3\hat{i} + \hat{k}), \vec{b} = \frac{1}{7}(2\hat{i} + 3\hat{j} - 6\hat{k})$, then the value of $(\vec{a} - 2\vec{b}) \cdot \{(\vec{a} \times \vec{b}) \times (2\vec{a} + \vec{b})\}$ is
The equation $x^2 - 3xy + 2y^2 + 3x - 5y + 2 = 0$ represents a pair of straight lines. If $\theta$ is the angle between them, then the value of $\cos \theta$ is equal to
Two adjacent sides of a parallelogram ABCD are given by $\vec{AB} = 2\hat{i} + 10\hat{j} + 11\hat{k}$ and $\vec{AD} = -\hat{i} + 2\hat{j} + 2\hat{k}$. The side AD is rotated by an acute angle $\alpha$ in the plane of parallelogram so that AD becomes AD'. If AD' makes a right angle with the side AB, then $\cos \alpha =$
$\cot^{-1}(2 \cdot 1^2) + \cot^{-1}(2 \cdot 2^2) + \cot^{-1}(2 \cdot 3^2) + \dots \dots \infty =$
The vectors $\vec{p} = \hat{i} + a\hat{j} + a^2\hat{k}, \vec{q} = \hat{i} + b\hat{j} + b^2\hat{k}$ and $\vec{r} = \hat{i} + c\hat{j} + c^2\hat{k}$ are non-coplanar and $\begin{vmatrix} a & a^2 & 1+a^3 \\ b & b^2 & 1+b^3 \\ c & c^2 & 1+c^3 \end{vmatrix} = 0$ then the value of $(abc)$ is
With usual notation, in a triangle ABC $\frac{b+c}{11} = \frac{c+a}{12} = \frac{a+b}{13}$, then the value of $\cos B$ is equal to
The equation of a line passing through the point $(-1, 2, 3)$ and perpendicular to the lines $\frac{x}{2} = \frac{y-1}{-3} = \frac{z+2}{-2}$ and $\frac{x+3}{-1} = \frac{y+3}{2} = \frac{z-1}{3}$ is
If $A = \begin{bmatrix} 1 & -2 & 2 \\ 0 & 2 & -3 \\ 3 & -2 & 4 \end{bmatrix}$ then $A(I + \text{adj } A) =$
If $\vec{c} = 5\vec{a} + 6\vec{b}$ and $3\vec{c} = \vec{a} - 4\vec{b}$ then}