Question:

The equation of the curve passing through origin and satisfying $(1 + x^2) \frac{dy}{dx} + 2xy = 4x^2$ is ______.

Show Hint

In many LDE problems structured like $f(x) \frac{dy}{dx} + f'(x)y = Q(x)$, you can bypass the IF formula entirely! Recognize that the LHS is exactly the product rule expansion of $\frac{d}{dx}[y \cdot f(x)]$. Integrating both sides directly gives $y \cdot f(x) = \int Q(x) dx$.
Updated On: Jun 19, 2026
  • $y(1 + x^2) = 4x^3$
  • $4(1 + x^2) = 4 + y^2$
  • $3y(1 + x^2) = 4x^3$
  • $1 + y^2 = 4x^3 + 1$
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
We are given a first-order differential equation and an initial value condition (it passes through the origin, meaning $x=0, y=0$). We need to find the specific particular solution.

Step 2: Key Formula or Approach:

The given equation can be arranged into the standard form of a Linear Differential Equation:
$\frac{dy}{dx} + P(x)y = Q(x)$.
We solve this by finding the Integrating Factor (IF), which is $e^{\int P(x) dx}$.
The general solution is then given by: $y \times \text{IF} = \int (Q(x) \times \text{IF}) dx + C$.

Step 3: Detailed Explanation:

Rewrite the given equation by dividing entirely by $(1 + x^2)$:
$$\frac{dy}{dx} + \left( \frac{2x}{1 + x^2} \right) y = \frac{4x^2}{1 + x^2}$$
Here, $P(x) = \frac{2x}{1+x^2}$ and $Q(x) = \frac{4x^2}{1+x^2}$.
Find the Integrating Factor (IF):
$$\text{IF} = e^{\int \frac{2x}{1+x^2} dx}$$
Since the numerator is the exact derivative of the denominator, the integral is $\ln|1+x^2|$.
$$\text{IF} = e^{\ln(1+x^2)} = 1 + x^2$$
Write the general solution equation:
$$y(1 + x^2) = \int \left( \frac{4x^2}{1 + x^2} \times (1 + x^2) \right) dx + C$$
The $(1+x^2)$ terms brilliantly cancel out on the right side!
$$y(1 + x^2) = \int 4x^2 \, dx + C$$
$$y(1 + x^2) = \frac{4x^3}{3} + C$$
Now, apply the initial condition: the curve passes through the origin $(0,0)$.
$$0(1 + 0^2) = \frac{4(0)^3}{3} + C \implies 0 = 0 + C \implies C = 0$$
Substitute $C=0$ back into the solution:
$$y(1 + x^2) = \frac{4x^3}{3}$$
Multiply both sides by 3 to clear the fraction:
$$3y(1 + x^2) = 4x^3$$

Step 4: Final Answer:

The equation of the curve is $3y(1 + x^2) = 4x^3$, which matches option (c).
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