Given: (I) \(\mathrm{H_2(g)} + \tfrac12\mathrm{O_2(g)} \rightarrow \mathrm{H_2O}(l)\); \(\Delta H^\circ_{298\,K} = -285.9\ \mathrm{kJ\,mol^{-1}}\)
(II) \(\mathrm{H_2(g)} + \tfrac12\mathrm{O_2(g)} \rightarrow \mathrm{H_2O(g)}\); \(\Delta H^\circ_{298\,K} = -241.8\ \mathrm{kJ\,mol^{-1}}\)
The molar enthalpy of vapourisation of water will be :