Question:

Photons of an electromagnetic radiation has an energy 11keV each. To which region of electromagnetic spectrum does it belong ?

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Convert the photon energy to wavelength using \(\lambda(\text{\AA}) \approx 12400/E(\mathrm{eV})\) and compare with the spectrum.
Updated On: Oct 31, 2026
  • X-ray region
  • Ultra violet region
  • Infrared region
  • Visible region
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The Correct Option is A

Solution and Explanation

\(E = 11\ \mathrm{keV} = 11\times10^{3}\ \mathrm{eV}\).
\(\lambda = \dfrac{hc}{E} = \dfrac{12400\ \mathrm{eV\,\text{\AA}}}{11\times10^{3}\ \mathrm{eV}} \approx 1.13\ \text{\AA} = 0.113\ \mathrm{nm}\).
Wavelengths of about 0.01 to 10 nm belong to X-rays; UV is 10-400 nm, visible 400-700 nm, IR above 700 nm.
Answer: (1) X-ray region
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