Aryl fluoride may be prepared from arene diazonium chloride using :
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- \(\mathrm{HBF_4/\Delta}\)
- \(\mathrm{HBF_4/NaNO_2,\ Cu,\ \Delta}\)
- \(\mathrm{CuF/HF}\)
- \(\mathrm{Cu/HF}\) 0
The Correct Option is A
Solution and Explanation
Instead, the arene diazonium chloride is treated with fluoroboric acid \(\mathrm{HBF_4}\), which precipitates the diazonium tetrafluoroborate \(\mathrm{ArN_2^+BF_4^-}\).
Heating this salt (\(\Delta\)) gives \(\mathrm{ArF + BF_3 + N_2}\). This is the Balz-Schiemann reaction.
So the reagent is \(\mathrm{HBF_4/\Delta}\).
Answer: (1) \(\mathrm{HBF_4/\Delta}\)
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