Question:

The element with which of the following outer electron configuration may exhibit the largest number of oxidation states in its compounds :

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The number of oxidation states depends on how many unpaired electrons in the 3d and 4s subshells are available; it is maximum near the middle of the series.
Updated On: Oct 31, 2026
  • \(3d^54s^2\)
  • \(3d^84s^2\)
  • \(3d^74s^2\)
  • \(3d^64s^2\)
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The Correct Option is A

Solution and Explanation

The oxidation states of 3d elements arise from loss of 4s electrons and unpaired 3d electrons.
\(3d^54s^2\) is manganese: it has 7 valence electrons (5 in 3d, 2 in 4s) and shows every oxidation state from +2 to +7, the largest number among the 3d elements.
\(3d^64s^2\) (Fe) shows mainly +2, +3 (rarely +4, +6); \(3d^74s^2\) (Co) shows +2, +3 (+4); \(3d^84s^2\) (Ni) shows mainly +2 (+3, +4).
Mn, with the maximum number of unpaired d electrons (five), has the largest range.
Answer: (1) \(3d^54s^2\)
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