If a carrier wave \(c(t) = A \sin \omega_c t\) is amplitude modulated by a modulator signal \(m(t) = A \sin \omega_m t\) then the equation of modulated signal \([C_m(t)]\) and its modulation index are respectively
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- \(C_m(t) = A(1+\sin\omega_m t)\sin\omega_c t\) and 2
- \(C_m(t) = A(1+\sin\omega_m t)\sin\omega_m t\) and 1
- \(C_m(t) = A(1+\sin\omega_m t)\sin\omega_c t\) and 1
- \(C_m(t) = A(1+\sin\omega_c t)\sin\omega_m t\) and 2
The Correct Option is C
Solution and Explanation
Here \(A_c = A\) and \(A_m = A\), so \(C_m(t) = A(1+\sin\omega_m t)\sin\omega_c t\).
Modulation index \(\mu = \dfrac{A_m}{A_c} = \dfrac{A}{A} = 1\).
This matches option (3).
Answer: (3) \(C_m(t) = A(1+\sin\omega_m t)\sin\omega_c t\) and 1
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