An element having an atomic radius of 0.14 nm crystallizes in an \(fcc\) unit cell. What is the length of a side of the cell ?
Show Hint
- 0.56 nm
- 0.24 nm
- 0.96 nm
- 0.4 nm
The Correct Option is D
Solution and Explanation
\(a = \dfrac{4r}{\sqrt2} = 2\sqrt2\,r\).
\(a = 2\times1.414\times0.14\ \mathrm{nm} = 0.396\ \mathrm{nm}\approx 0.4\ \mathrm{nm}\).
Answer: (4) 0.4 nm
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