Zn\(^{2+}\) salts are colourless. Why?
Zinc salts, specifically those containing the \( \text{Zn}^{2+} \) ion, are colorless due to their electronic configuration.
The electronic configuration of a \( \text{Zn}^{2+} \) ion is:
\( 1s^2\,2s^2\,2p^6\,3s^2\,3p^6\,3d^{10} \)
This configuration shows a completely filled \( 3d \) subshell, with no unpaired electrons.
In transition metal ions, color typically arises from \( d \rightarrow d \) electronic transitions—when electrons jump between split \( d \)-orbital energy levels by absorbing visible light. However, in \( \text{Zn}^{2+} \), these transitions are not possible because:
As a result, \( \text{Zn}^{2+} \) ions do not absorb visible light, and their salts appear colorless in solution.
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).