Write the IUPAC name of the product formed in the Reimer-Tiemann reaction.
Write the IUPAC name of the product formed in the Reimer-Tiemann reaction.
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Solution and Explanation
Reimer-Tiemann Reaction
The Reimer-Tiemann reaction is a method used for the ortho-formylation of phenols. It involves the introduction of a formyl group (-CHO) to the aromatic ring of phenol using chloroform (CHCl₃) in the presence of a strong base, typically sodium hydroxide (NaOH).
General Reaction:
The general reaction can be represented as: \[ \text{C}_6\text{H}_5\text{OH} + \text{CHCl}_3 + \text{NaOH} \rightarrow \text{2-formylphenol} + \text{by-products} \]
Product Formed:
The product of the Reimer-Tiemann reaction is 2-formylphenol, also known as ortho-hydroxybenzaldehyde.
IUPAC Name:
The IUPAC name of the product formed in the Reimer-Tiemann reaction is 2-formylphenol.
Structure of the Product:
In this reaction, the formyl group (-CHO) is added to the ortho position (adjacent to the hydroxyl group -OH) on the benzene ring.
Conclusion:
Therefore, the IUPAC name of the product formed in the Reimer-Tiemann reaction is 2-formylphenol.
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