Question

Write the hybridization and magnetic character of the complex \([Ni(CO)_4]\) on the basis of valence bond theory.
[Atomic No. Ni = 28]

Hint:

The hybridization of a metal complex depends on the geometry and the nature of the ligands. CO is a strong field ligand that leads to electron pairing, resulting in a tetrahedral geometry.

Answer 1

For the complex \([Ni(CO)_4]\), nickel is in the +0 oxidation state. The electronic configuration of Ni is \( 3d^8 4s^2 \). - Hybridization: In \([Ni(CO)_4]\), the CO ligands are strong field ligands that cause the pairing of the 3d electrons, resulting in the hybridization \( sp^3 \). The geometry of the complex is tetrahedral. 
- Magnetic character: Since all electrons are paired in the complex, it is diamagnetic. 

Explanation: 
- In the presence of CO, which is a strong field ligand, the 3d electrons are paired, leading to a tetrahedral geometry with \( sp^3 \) hybridization and no unpaired electrons, thus the complex is diamagnetic.