Write the formulas of: (a) Mercury(I) tetrathiocyanato-S-cobaltate(III)
(b) Dichloridobis(ethane-1,2-diamine)platinum(IV) nitrate
(b) Dichloridobis(ethane-1,2-diamine)platinum(IV) nitrate
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Solution and Explanation
IUPAC names of coordination compounds encode the formula systematically.
Step 2: Analysis (a)
Mercury(I) is $Hg_2^{2+}$ (the counter cation). The complex anion is tetrathiocyanato-S-cobaltate(III): four thiocyanate ligands ($SCN^-$, bound through S), cobalt in $+3$ state. Anion: $[Co(NCS)_4]^-$ but since S-bonded it is written $[Co(SCN)_4]^-$. Full formula: $Hg_2[Co(SCN)_4]$.
Step 3: Analysis (b)
Dichloridobis(ethane-1,2-diamine)platinum(IV): two $Cl^-$ and two en ligands, Pt in $+4$ state. Net charge of complex cation: $+4 - 2 = +2$. Counter anion: nitrate ($NO_3^-$), two needed. Formula: $[Pt(en)_2Cl_2](NO_3)_2$.
Final Answer:
(a) $Hg_2[Co(SCN)_4]$
(b) $[Pt(en)_2Cl_2](NO_3)_2$
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