Would you expect benzaldehyde to be more reactive or less reactive in nucleophilic addition reactions than propanal? Justify your answer.
Benzaldehyde is less reactive in nucleophilic addition reactions than propanal due to the presence of a resonance-stabilized benzene ring attached to its carbonyl group.
In benzaldehyde, the carbonyl carbon is less electrophilic because of resonance interaction between the carbonyl group and the aromatic ring:
\[ \text{Ph-CHO} \leftrightarrow \text{Ph-C}^{\delta+}\text{=O}^{\delta-} \]
This delocalization reduces the partial positive charge on the carbonyl carbon, making it less susceptible to nucleophilic attack.
In contrast, propanal (\( \text{CH}_3\text{CH}_2\text{CHO} \)) has no such resonance stabilization. The electron-withdrawing nature of the carbonyl group is unopposed, so the carbonyl carbon remains strongly electrophilic and readily undergoes nucleophilic addition.
Benzaldehyde: Reactivity reduced due to resonance with benzene ring.
Propanal: More reactive as no resonance stabilization exists.
A student is given one compound among the following compounds that gives positive test with Tollen's reagent. The compound is: 
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).