To solve this problem, we need to compare the acidity of phenol (C6H5OH), alcohol (ROH), and water (H2O).
1. Understanding Acid Strength:
Acid strength depends on the ability of the molecule to donate a proton (H+). This is determined by the stability of the conjugate base formed after proton loss.
2. Phenol (C6H5OH) vs Alcohol (ROH):
Phenol is more acidic than alcohol because the negative charge on the oxygen in the phenoxide ion (C6H5O-) is stabilized by resonance with the aromatic ring. In contrast, the negative charge on the oxygen in the alkoxide ion (RO-) is not stabilized, making alcohol less acidic than phenol.
3. Phenol (C6H5OH) vs Water (H2O):
Water (H2O) is a weaker acid than phenol. Although water can donate a proton to form the hydroxide ion (OH-), the conjugate base of phenol is more stable due to resonance stabilization.
4. Conclusion:
The correct order of acid strength is: Water > Phenol > Alcohol.
Final Answer:
The correct option is (D) H2O > C6H5OH > ROH.


A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).