Which is the correct IUPAC name for

To solve the problem, we need to determine the correct IUPAC name for the given compound, which is a benzene ring with a methyl group (CH\(_3\)) and a chlorine (Cl) substituent.
1. Identifying the Structure:
The compound is a benzene ring with two substituents: a methyl group (CH\(_3\)) and a chlorine atom (Cl). From the diagram, the methyl group and chlorine are positioned on the benzene ring, and we need to determine their relative positions.
2. Determining the Positions:
In the benzene ring, the positions of substituents are numbered 1 through 6. Let’s assume the methyl group is at position 1 (as is common in IUPAC naming to give the lowest possible numbers). The diagram shows the methyl group and chlorine in a para relationship (opposite each other, 1,4-positions). Thus, if the methyl group is at position 1, the chlorine is at position 4.
3. Naming the Compound:
In IUPAC nomenclature for a disubstituted benzene, the substituents are named in alphabetical order, and the lowest possible numbers are assigned to their positions. Here, the substituents are:
- Chloro (Cl)
- Methyl (CH\(_3\))
Alphabetically, "chloro" (C) comes before "methyl" (M), so "chloro" is assigned the lowest possible number. If methyl is at position 1, chlorine is at position 4, making the name 1-methyl-4-chlorobenzene. Alternatively, if chlorine is at position 1, methyl is at position 4, giving 1-chloro-4-methylbenzene. Since "chloro" precedes "methyl" alphabetically, 1-chloro-4-methylbenzene is preferred.
4. Evaluating the Options:
- Option A: Methylchlorobenzene
This name does not follow IUPAC rules, as it lacks positional numbers and is not a systematic name. Incorrect.
- Option B: Toluene
Toluene is methylbenzene (C\(_6\)H\(_5\)CH\(_3\)), with only a methyl group and no chlorine. Incorrect.
- Option C: 1-Chloro-4-Methylbenzene
This matches our deduced name: chlorine at position 1, methyl at position 4, following alphabetical priority. Correct.
- Option D: 1-Methyl-4-Chlorobenzene
This is the same compound as option C but prioritizes "methyl" over "chloro," which violates the alphabetical rule in IUPAC naming. Incorrect.
Final Answer:
The correct IUPAC name for the compound is 1-chloro-4-methylbenzene (option C).
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Write two consequences of lanthanide contraction.