Step 1: Understand the differential equation
The given differential equation is dy/dx + y = 0, which is a first-order linear differential equation.
Step 2: General form of a first-order linear differential equation
A first-order linear differential equation can be written as dy/dx + P(x)y = Q(x). In this case, P(x) = 1 and Q(x) = 0.
Step 3: Solve the differential equation
To solve, use the integrating factor method.
The integrating factor (IF) = e^(∫P(x) dx) = e^(∫1 dx) = e^x.
Step 4: Multiply the entire equation by the integrating factor
e^x * dy/dx + e^x * y = 0
This can be written as d/dx (y * e^x) = 0.
Step 5: Integrate both sides
∫ d/dx (y * e^x) dx = ∫ 0 dx
y * e^x = C, where C is the constant of integration.
Step 6: Express the general solution
y = C * e^(-x).
Step 7: Number of arbitrary constants
The general solution contains one arbitrary constant C.
Final Answer: (B) 1
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).