Question:

The intermediate formed during the slowest step involved in the dehydration of alcohol is:

Show Hint

In acid-catalysed dehydration of alcohol, the slowest step is loss of water and formation of carbocation.
Updated On: Jun 29, 2026
  • Protonated alcohol
  • Carbanion
  • Free radical
  • Carbocation
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Concept:
Dehydration of alcohol means removal of water from alcohol to form alkene. In acid-catalysed dehydration of alcohol, the reaction generally proceeds through three steps. First, alcohol gets protonated. Second, water leaves from the protonated alcohol. Third, deprotonation gives alkene. The slowest step is the removal of water, which forms a carbocation.

Step 1: Protonation of alcohol.
Alcohol first reacts with acid. \[ ROH+H^+ \rightarrow ROH_2^+ \] The product is protonated alcohol. This makes water a good leaving group.

Step 2: Loss of water in slow step.
The protonated alcohol loses water. \[ ROH_2^+ \rightarrow R^+ + H_2O \] This step forms carbocation. This is the slowest step because bond breaking occurs here.

Step 3: Formation of alkene.
The carbocation loses a proton to form alkene. \[ R^+ \rightarrow \text{Alkene} \] Therefore, the intermediate formed during the slowest step is carbocation. Hence: \[ \boxed{\text{(D) Carbocation}} \]
Was this answer helpful?
0
0

Top CBSE CLASS XII Chemistry Questions

View More Questions