2-Bromobutane to but-2-ene
To convert 2-bromobutane into but-2-ene, an elimination reaction (E2 mechanism) is used. This reaction requires a strong base like potassium hydroxide (KOH).
In the E2 reaction, the base abstracts a proton from the β-carbon (the carbon adjacent to the one bonded to the bromine), and the bromine atom leaves simultaneously, resulting in the formation of a double bond (alkene).
\( \text{CH}_3\text{-CHBr-CH}_2\text{-CH}_3 \xrightarrow{\text{alc. KOH, heat}} \text{CH}_3\text{-CH=CH-CH}_3 \)
Product: But-2-ene (major product due to Zaitsev’s rule, which favors the more substituted alkene).
A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).