Question:
The equation of the parabola with focus \((2,0)\) and vertex \((1,0)\) is
The equation of the parabola with focus \((2,0)\) and vertex \((1,0)\) is
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For a parabola opening right with vertex \((h,k)\), use \((y-k)^2=4a(x-h)\).
Updated On: May 7, 2026
- \(y^2=4x\)
- \(y^2=4x-4\)
- \(y^2=4(x+1)\)
- \(y^2=-4(x-1)\)
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The Correct Option is B
Solution and Explanation
Step 1: Vertex is \((1,0)\) and focus is \((2,0)\).
Step 2: Since focus is to the right of vertex, parabola opens towards positive \(x\)-axis.
Step 3: Standard form: \[ (y-k)^2=4a(x-h) \] Here, \[ (h,k)=(1,0) \]
Step 4: Distance between vertex and focus: \[ a=2-1=1 \]
Step 5: \[ y^2=4(1)(x-1) \] \[ y^2=4x-4 \] \[ \boxed{y^2=4x-4} \]
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