directly proportional to the charge within the shell
inversely proportional to $R^2$
same as that outside the shell
zero
maximum at the centre
Show Solution
Verified By Collegedunia
The Correct Option isD
Solution and Explanation
Step 1: Concept
Use Gauss's Law: $\oint E \cdot dA = \frac{q_{enclosed}}{\epsilon_0}$.
Step 2: Meaning
For any Gaussian surface inside the shell ($r < R$), the enclosed charge is zero because all charge resides on the outer surface.
Step 3: Analysis
Since $q_{enclosed} = 0$, then $E \cdot A = 0$.
Step 4: Conclusion
The electric field $E$ must be zero everywhere inside the shell.
Final Answer: (D)