Question:
The inward and outward electric flux from a closed surface are \( 6\times10^4 \,\text{Nm}^2\text{C}^{-1} \) and \( 3\times10^4 \,\text{Nm}^2\text{C}^{-1} \). Then the net charge (in coulomb) inside the closed surface is
The inward and outward electric flux from a closed surface are \( 6\times10^4 \,\text{Nm}^2\text{C}^{-1} \) and \( 3\times10^4 \,\text{Nm}^2\text{C}^{-1} \). Then the net charge (in coulomb) inside the closed surface is
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Outward flux positive, inward flux negative.
Updated On: Apr 21, 2026
- \( -6\times10^4 \varepsilon_0 \)
- \( 6\times10^4 \varepsilon_0 \)
- \( 3\times10^4 \varepsilon_0 \)
- \( 9\times10^4 \varepsilon_0 \)
- \( -3\times10^4 \varepsilon_0 \)
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The Correct Option is
Solution and Explanation
Concept:
\[
\Phi_{net} = \Phi_{out} - \Phi_{in}
\]
Step 1: Net flux.
\[ \Phi = 3\times10^4 - 6\times10^4 = -3\times10^4 \]
Step 2: Gauss law.
\[ q = \varepsilon_0 \Phi = -3\times10^4 \varepsilon_0 \]
Step 1: Net flux.
\[ \Phi = 3\times10^4 - 6\times10^4 = -3\times10^4 \]
Step 2: Gauss law.
\[ q = \varepsilon_0 \Phi = -3\times10^4 \varepsilon_0 \]
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