A conductor with an air core cavity inside, is charged to attain the surface charge density of \(\sigma\). If E is the magnitude of electric field and V is the potential, then inside the cavity
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For a charged conductor with a cavity, the electric field inside the cavity is zero in electrostatic equilibrium.
Step 1:
In electrostatic equilibrium, electric field inside a conductor is $E = 0$.
Step 2:
For an empty cavity inside a conductor with no charge inside, $E = 0$ in the cavity.
Step 3:
Since $E = -\dfrac{dV}{dr} = 0$, potential remains constant inside the cavity.
Step 4:
The constant potential inside the cavity is equal to the surface potential of the conductor, hence $V \neq 0$. Final Answer: Option D: $V \neq 0 \text{ and } E = 0$.