Question:
The beats are produced by two sound sources of same amplitude and of nearly equal frequencies. The maximum intensity of beats will be_____when compared to that of one source is.
The beats are produced by two sound sources of same amplitude and of nearly equal frequencies. The maximum intensity of beats will be_____when compared to that of one source is.
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When two equal-amplitude waves interfere constructively, amplitude doubles and intensity becomes four times.
Updated On: May 7, 2026
- Same
- Double
- Four times
- Eight times
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The Correct Option is C
Solution and Explanation
Concept:
Intensity of sound is proportional to square of amplitude: \[ I\propto A^2 \]
Step 1: Let amplitude of each source be \(A\).
Step 2: At maximum intensity of beats, the two waves interfere constructively.
Step 3: Resultant amplitude becomes: \[ A_{max}=A+A=2A \]
Step 4: Intensity due to one source: \[ I\propto A^2 \]
Step 5: Maximum intensity: \[ I_{max}\propto (2A)^2=4A^2 \]
Step 6: Therefore: \[ I_{max}=4I \] \[ \boxed{\text{Four times}} \]
Intensity of sound is proportional to square of amplitude: \[ I\propto A^2 \]
Step 1: Let amplitude of each source be \(A\).
Step 2: At maximum intensity of beats, the two waves interfere constructively.
Step 3: Resultant amplitude becomes: \[ A_{max}=A+A=2A \]
Step 4: Intensity due to one source: \[ I\propto A^2 \]
Step 5: Maximum intensity: \[ I_{max}\propto (2A)^2=4A^2 \]
Step 6: Therefore: \[ I_{max}=4I \] \[ \boxed{\text{Four times}} \]
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