Question:

A source of sound of frequency 500Hz is moving towards an observer with velocity $30m/s$. The speed of sound is $330m/s$. The frequency heard by the observer will be:

Show Hint

Source moves towards = Frequency increases. If the source velocity is 10% of sound speed, the frequency increases by roughly 10%.
  • 450 Hz
  • 550 Hz
  • 600 Hz
  • 500 Hz
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The Correct Option is B

Solution and Explanation


Step 1: Concept

Apply the Doppler Effect formula for a source moving towards a stationary observer: $n' = n (\frac{v}{v - v_s})$.

Step 2: Meaning

Here, $n=500$ Hz, $v=330$ m/s, and $v_s=30$ m/s.

Step 3: Analysis

$n' = 500 (\frac{330}{330 - 30}) = 500 (\frac{330}{300}) = 500 \times 1.1$.

Step 4: Conclusion

$n' = 550$ Hz.
Final Answer: (B)
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