Question

If the volume of a room is doubled and the total absorption is halved, the reverberation time will:

• A. Remain unchanged
• B. Be doubled
• C. Become four times
• D. Be halved

Hint:

Double the size ($ \times 2$) and half the sponges ($ \times 2$) = 4 times the echo time.

Answer 1

The Correct Option is C

Step 1: Concept
Use Sabine's Formula: $T = \frac{0.16V}{A}$, where $V$ is volume and $A$ is total absorption.

Step 2: Meaning
$T$ is directly proportional to volume ($V$) and inversely proportional to absorption ($A$).

Step 3: Analysis
If $V' = 2V$ and $A' = A/2$, then $T' = \frac{0.16(2V)}{A/2} = 4 \times (\frac{0.16V}{A}) = 4T$.

Step 4: Conclusion
The reverberation time will become four times the original.
Final Answer: (C)