Propan-2-ol on oxidation with $CrO_{3}$ gives :
Show Hint
- Propanal
- Propanoic acid
- Propene
- Propanone
The Correct Option is D
Solution and Explanation
The oxidation of alcohols depends on the class of the alcohol (primary, secondary, or tertiary) and the strength of the oxidizing agent.
Step 2: Meaning
Propan-2-ol ($CH_3-CH(OH)-CH_3$) is a secondary alcohol, as the carbon bearing the -OH group is attached to two other carbon atoms. $CrO_{3}$ is a strong oxidizing agent.
Step 3: Analysis
Primary alcohols oxidize to aldehydes and subsequently to carboxylic acids. Secondary alcohols oxidize to form ketones. Because a ketone lacks a hydrogen atom on the carbonyl carbon, it resists further oxidation under normal conditions.
Step 4: Conclusion
Oxidation of the secondary alcohol propan-2-ol yields a ketone with three carbon atoms. This ketone is propanone (commonly known as acetone).
Final Answer: (D)
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