Question

In A gamete chromosome number is 2. In B chromosome number in meiocyte is four times higher than A. In C the chromosome number in gamete is three times higher than B. Identify A, B and C respectively.

• A. A→ Fruit fly, B→ Butterfly, C→ Potato
• B. A→ Haplopappus, B→ Fruit fly, C→ Potato
• C. A→ Rice, B→ Fruit fly, C→ Onion
• D. A→ Haplopappus, B→ Fruit fly, C→ Onion

Hint:

Important chromosome numbers: Haplopappus = \(2n=4\), Fruit fly = \(2n=8\), Onion = \(2n=16\) gametic count \(=8\), commonly used examples must be memorized.

Answer 1

The Correct Option is D

Step 1: Determine A.
Gamete chromosome number: \[ n=2 \] This corresponds to: \[ \text{Haplopappus } (2n=4) \] Hence A = Haplopappus.

Step 2: Determine B.
Meiocyte chromosome number is four times A. \[ 4\times2=8 \] Thus: \[ 2n=8 \] Fruit fly has: \[ 2n=8 \] Hence B = Fruit fly.

Step 3: Determine C.
Gamete chromosome number is three times B. \[ 3\times8=24 \] Thus: \[ n=24 \] \[ 2n=48 \] Onion possesses: \[ 2n=48 \] Hence C = Onion. \[ \boxed{\text{A→Haplopappus,\; B→Fruit fly,\; C→Onion}} \]