Question:
What are X and Y in the following reactions?
\[
2X_2(g)+2H_2O(l)\rightarrow4H^+(aq)+4X^-(aq)+O_2(g)
\]
\[
Y_2(g)+H_2O(l)\rightarrow HY(aq)+HOY(aq)
\]
What are X and Y in the following reactions?
\[
2X_2(g)+2H_2O(l)\rightarrow4H^+(aq)+4X^-(aq)+O_2(g)
\]
\[
Y_2(g)+H_2O(l)\rightarrow HY(aq)+HOY(aq)
\]
Show Hint
Only fluorine oxidizes water to oxygen. Chlorine disproportionates to HCl and HOCl.
Updated On: Jun 15, 2026
- \(X=F,\;Y=I\)
- \(X=I,\;Y=Cl\)
- \(X=F,\;Y=Cl\)
- \(X=Cl,\;Y=I\)
Show Solution
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The Correct Option is C
Solution and Explanation
Concept:
Halogens react differently with water depending upon oxidizing power.
Fluorine is strongest oxidizing agent.
Chlorine disproportionates in water.
Step 1: Identify X. Reaction: \[ 2X_2+2H_2O\rightarrow4H^++4X^-+O_2 \] Only fluorine oxidizes water to oxygen. Reaction: \[ 2F_2+2H_2O\rightarrow4HF+O_2 \] Thus \[ X=F \]
Step 2: Identify Y. Reaction: \[ Y_2+H_2O\rightarrow HY+HOY \] This is disproportionation reaction of chlorine. Reaction: \[ Cl_2+H_2O\rightarrow HCl+HOCl \] Thus \[ Y=Cl \]
Step 3: Final answer. Hence pair becomes \[ X=F,\qquad Y=Cl \] Therefore answer is \[ \boxed{C} \]
Step 1: Identify X. Reaction: \[ 2X_2+2H_2O\rightarrow4H^++4X^-+O_2 \] Only fluorine oxidizes water to oxygen. Reaction: \[ 2F_2+2H_2O\rightarrow4HF+O_2 \] Thus \[ X=F \]
Step 2: Identify Y. Reaction: \[ Y_2+H_2O\rightarrow HY+HOY \] This is disproportionation reaction of chlorine. Reaction: \[ Cl_2+H_2O\rightarrow HCl+HOCl \] Thus \[ Y=Cl \]
Step 3: Final answer. Hence pair becomes \[ X=F,\qquad Y=Cl \] Therefore answer is \[ \boxed{C} \]
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