Question:
Total number of ATP produced per one molecule of G-3-P in aerobic respiration is:
Total number of ATP produced per one molecule of G-3-P in aerobic respiration is:
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One molecule of glucose gives 38 ATP (classical count). Since G3P represents half of glucose after investment phase, net yield becomes 19 ATP.
Updated On: Jun 17, 2026
- 16
- 17
- 18
- 19
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The Correct Option is D
Solution and Explanation
Concept:
One molecule of Glyceraldehyde-3-phosphate (G3P) enters glycolysis midway and subsequently undergoes complete aerobic oxidation.
Step 1: ATP produced during glycolysis from one G3P.
\[ 1\;NADH = 3\;ATP \] \[ 2\;ATP \text{ (substrate level)} \] Total: \[ 3+2=5\;ATP \]
Step 2: Oxidative decarboxylation of pyruvate.
\[ 1\;NADH=3\;ATP \]
Step 3: Krebs cycle contribution.
From one Acetyl Co-A: \[ 3NADH=9ATP \] \[ 1FADH_2=2ATP \] \[ 1ATP=1ATP \] Total: \[ 12ATP \]
Step 4: Total ATP calculation.
\[ 5+3+12=20ATP \] Considering transport cost of one ATP: \[ 20-1=19ATP \] \[ \boxed{19} \]
Step 1: ATP produced during glycolysis from one G3P.
\[ 1\;NADH = 3\;ATP \] \[ 2\;ATP \text{ (substrate level)} \] Total: \[ 3+2=5\;ATP \]
Step 2: Oxidative decarboxylation of pyruvate.
\[ 1\;NADH=3\;ATP \]
Step 3: Krebs cycle contribution.
From one Acetyl Co-A: \[ 3NADH=9ATP \] \[ 1FADH_2=2ATP \] \[ 1ATP=1ATP \] Total: \[ 12ATP \]
Step 4: Total ATP calculation.
\[ 5+3+12=20ATP \] Considering transport cost of one ATP: \[ 20-1=19ATP \] \[ \boxed{19} \]
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