Question:

In a circle with center \(O\), a \(6\) cm long chord is at a distance \(4\) cm from the center. Then the length of diameter is

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The perpendicular from the center to a chord bisects the chord.
  • \(5\) cm
  • \(10\) cm
  • \(15\) cm
  • \(8\) cm
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The Correct Option is B

Solution and Explanation


Step 1:
Chord length is \(6\) cm, so half chord is: \[ \frac{6}{2}=3\text{ cm} \]

Step 2:
Distance from center to chord is: \[ 4\text{ cm} \]

Step 3:
Radius, half chord, and perpendicular distance form a right triangle. \[ r^2=3^2+4^2 \] \[ r^2=9+16=25 \] \[ r=5\text{ cm} \]

Step 4:
Diameter is: \[ 2r=2(5)=10\text{ cm} \] \[ \boxed{10\text{ cm}} \]
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