Question:

If $\sin^{-1} \frac{5}{x} + \sin^{-1} \frac{12}{x} = \frac{\pi}{2}$ then $x =$

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If the sum of two inverse sines is $\pi/2$, the arguments follow the Pythagorean triplet rule: $a^2 + b^2 = x^2$.
  • 12
  • 7
  • 13
  • 15
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The Correct Option is C

Solution and Explanation


Step 1: Concept

Use the identity $\sin^{-1} \alpha + \cos^{-1} \alpha = \pi/2$.

Step 2: Meaning

If $\sin^{-1} \frac{5}{x} + \sin^{-1} \frac{12}{x} = \pi/2$, then it implies $\sin^{-1} \frac{12}{x} = \cos^{-1} \frac{5}{x}$.

Step 3: Analysis

For $\sin^{-1} \frac{12}{x}$ to equal $\cos^{-1} \frac{5}{x}$, we consider a right-angled triangle where the hypotenuse is $x$. By Pythagoras' theorem: $5^2 + 12^2 = x^2 \implies 25 + 144 = x^2 \implies 169 = x^2$.

Step 4: Conclusion

Therefore, $x = 13$.
Final Answer: (C)
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