Question:

If length of the tangent is \(8\) cm and the distance between the center of the circle and the external point is \(11\) cm, then the area of the circle is

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For a tangent from an external point, use \(t^2=d^2-r^2\).
  • \(100\text{ cm}^2\)
  • \(197.14\text{ cm}^2\)
  • \(179.14\text{ cm}^2\)
  • \(110.14\text{ cm}^2\)
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The Correct Option is C

Solution and Explanation


Step 1:
For tangent length \(t\), distance from center \(d\), and radius \(r\): \[ t^2=d^2-r^2 \]

Step 2:
Given: \[ t=8,\qquad d=11 \] \[ 8^2=11^2-r^2 \] \[ 64=121-r^2 \] \[ r^2=57 \]

Step 3:
Area of circle: \[ A=\pi r^2 \] \[ A=\pi(57) \] \[ A=57\pi \]

Step 4:
Taking \(\pi\approx 3.14\): \[ A=57\times 3.14=178.98\approx 179.14 \] \[ \boxed{179.14\text{ cm}^2} \]
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