Concept:
If \(A\) is an \(n \times n\) matrix, then:
\[
|kA|=k^n|A|
\]
where \(k\) is a scalar and \(n\) is the order of the matrix.
Step 1: The given matrix is:
\[
A=\begin{bmatrix}
a & b \\
c & d
\end{bmatrix}
\]
So, \(A\) is a \(2 \times 2\) matrix.
Step 2: Given:
\[
|A|=5
\]
Step 3: We need to find:
\[
|2A|
\]
Step 4: Since the matrix is of order \(2\), use the formula:
\[
|kA|=k^2|A|
\]
Step 5: Put \(k=2\):
\[
|2A|=2^2|A|
\]
\[
|2A|=4 \times 5
\]
\[
|2A|=20
\]
\[
\boxed{20}
\]