Step 1: Let:
\[
f(x)=2x^3+3x^2-36x+10
\]
Step 2: Differentiate:
\[
f'(x)=6x^2+6x-36
\]
\[
f'(x)=6(x^2+x-6)
\]
\[
f'(x)=6(x+3)(x-2)
\]
Step 3: Critical points:
\[
x=-3,\quad x=2
\]
Step 4: Second derivative:
\[
f''(x)=12x+6
\]
At \(x=2\):
\[
f''(2)=24+6=30>0
\]
Step 5: Since second derivative is positive, minimum occurs at:
\[
x=2
\]
\[
\boxed{2}
\]