Question:

Different structural information about glucose can be derived by reacting it with different reagents. Which of the following is correct?

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Glucose + 5 Acetic Anhydride $\rightarrow$ Pentaacetate. If it takes 5, there are 5 -OH groups!
Updated On: May 14, 2026
  • Reaction with HI confirms the presence of carbonyl groups.
  • Acetylation with acetic anhydride confirms the presence of -OH groups.
  • Reaction with bromine water confirms a straight chain.
  • Oxidation with nitric acid confirms the presence of secondary -OH groups.
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The Correct Option is B

Solution and Explanation


Step 1: Concept

Chemical tests are used to elucidate the structure of biomolecules like glucose by identifying specific functional groups.

Step 2: Analysis of Options

Reaction with HI/P yields n-hexane, confirming a straight chain. Bromine water (a mild oxidant) confirms the aldehyde group. Nitric acid (strong oxidant) confirms the primary alcohol group and the aldehyde.

Step 3: Correct Identification

Acetylation of glucose with acetic anhydride results in glucose pentaacetate, which confirms the presence of five hydroxyl (-OH) groups.

Step 4: Conclusion

The correct match is the use of acetic anhydride for -OH group confirmation. Final Answer: (B)
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