Consider a certain reaction \(A\) \(→\) \(Products\) with \(k = 2.0 \times 10^{-2 }s^{-1}\) . Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L-1.
k= 2.0 × 10-2 s-1
T= 100 s
[A]o= 1.0 moL-1
Since the unit of k is \(s^{-1}\) , the given reaction is a first order reaction.
Therefore, \(k = \frac {2.303}{t} log\ \frac {[A]_0}{[A]}\)
⇒ \(2.0 \times 10^{-2} s^{-1} = \frac {2.303}{100\ s} log\ \frac {1.0}{[A]}\)
⇒ \(2.0 \times 10^{-2} s^{-1} = \frac {2.303}{100 \ s} (-log\ A)\)
⇒ \(-log [A] = \frac {2.0\times 10^{-2} \times 100}{2.303}\)
⇒ \([A] = Antilog\ (-\frac {2.0 \times 10^{-2}\times 100}{2.303})\)
⇒ \([A]= 0.135\ mol \ L^{-1} (approximately)\)
Hence, the remaining concentration of A is \(0.135\ mol \ L^{-1}\).
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
| Experiment | Time/s-1 | Total pressure/atm |
| 1 | 0 | 0.5 |
| 2 | 100 | 0.6 |
The rate constant for the decomposition of \(N_2O_5\) at various temperatures is given below:
| T/°C | 0 | 20 | 40 | 60 | 80 |
| 105 x k/s-1 | 0.0787 | 1.70 | 25.7 | 178 | 2140 |
Draw a graph between ln k and \(\frac 1T\) and calculate the values of \(A\) and \(E_a\).
Predict the rate constant at 30 ºC and 50 ºC.
The rate constant for the decomposition of hydrocarbons is 2.418 x 10-5 s-1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.
Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with \(t_{\frac 12} = 3.00\ hours\). What fraction of sample of sucrose remains after \(8 \ hours\)?
The decomposition of hydrocarbon follows the equation
\(k = (4.5 \times 10^{11} s^{-1})e^{-28000 \ K/T }\)
\(Calculate\ E_a\).
Chemical kinetics is the description of the rate of a chemical reaction. This is the rate at which the reactants are transformed into products. This may take place by abiotic or by biological systems, such as microbial metabolism.
The speed of a reaction or the rate of a reaction can be defined as the change in concentration of a reactant or product in unit time. To be more specific, it can be expressed in terms of: (i) the rate of decrease in the concentration of any one of the reactants, or (ii) the rate of increase in concentration of any one of the products. Consider a hypothetical reaction, assuming that the volume of the system remains constant. R → P
Read More: Chemical Kinetics MCQ