Question:

Atomic radii is a useful property for determining many aspects of chemistry of elements such as physical and chemical properties. The periodic table greatly assists in finding a number of trends. The transition metals belong to group 3 - 12 and are generally characterised by partially filled d-orbitals in the free elements or their cations. The atomic radii of transition metals show a small decrease from left to right across a period, then remain nearly constant, and finally, slight increase towards the end of the series. The trend is a result of interplay between the increasing nuclear charge and the increasing shielding effect from the filling of d-orbitals. Initially the nuclear charge dominates, leading to decrease in size, but as more d-electrons are added, their shielding becomes more effective, balancing the increased nuclear charge and causing the radii to become constant.

The increase in size between 3d and 4d metals is much greater than between the 4d and 5d metals. The atomic radii of 2nd and 3rd series are almost the same due to lanthanoid contraction. Increase in density is also observed on moving from left to right in a period.

Why is there not much change in the atomic radius of the transition metals with the increase in atomic number ?

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New electrons enter the inner d subshell. Their shielding balances the rise in nuclear charge, so the radius stays almost constant.
Updated On: Oct 22, 2026
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Solution and Explanation

Step 1: Know where the electrons go:
Across a transition series, each new electron enters the inner (n-1)d subshell. The outer ns subshell stays almost the same.

Step 2: Compare the two opposing effects:
Nuclear charge rises by one unit for each element, which tends to pull the outer electrons in.
The added d electrons shield the outer ns electrons from the nucleus, which tends to push them out again.
After the first few elements, the shielding effect balances the rise in nuclear charge.
The effective nuclear charge on the outer electrons stays nearly constant.
So the atomic radius changes very little in the middle of the series.

Final Answer:
The increased shielding by the added (n-1)d electrons cancels the increase in nuclear charge, so the radii remain nearly constant.
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