To solve this question, let's analyze the assertion and reason provided.
Assertion (A):
The boiling point of ethanol is higher than that of methoxymethane.
Reason (R):
There is intramolecular hydrogen bonding in ethanol.
1. Boiling Points of Ethanol and Methoxymethane:
Ethanol (C2H5OH) has a higher boiling point compared to methoxymethane (CH3OCH3). The reason for this difference is primarily due to the presence of hydrogen bonding in ethanol.
2. Hydrogen Bonding in Ethanol:
Ethanol exhibits intermolecular hydrogen bonding between the -OH group of one ethanol molecule and the hydrogen of another ethanol molecule. This strong intermolecular force requires more energy to break, resulting in a higher boiling point for ethanol compared to methoxymethane.
3. Evaluation of Assertion (A):
The assertion that ethanol has a higher boiling point than methoxymethane is correct. Methoxymethane, a simple ether, does not exhibit hydrogen bonding, resulting in a lower boiling point compared to ethanol.
4. Evaluation of Reason (R):
The reason provided is not entirely accurate. While it is true that ethanol has hydrogen bonding, it is intermolecular hydrogen bonding, not intramolecular hydrogen bonding, that influences the boiling point. Therefore, the reason is incorrect.
5. Conclusion:
The assertion is correct, but the reason is incorrect. Ethanol has a higher boiling point due to intermolecular hydrogen bonding, not intramolecular hydrogen bonding.
Final Answer:
The correct option is that the assertion is true, but the reason is false.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.
Write the IUPAC names of the following compounds:
Write structures of the compounds whose IUPAC names are as follows:
(i)2-Methylbutan-2-ol
(ii)1-Phenylpropan-2-ol
(iii)3,5-Dimethylhexane -1,3,5-triol
(iv)2,3-Diethylphenol
(v)1- Ethoxypropane
(vi)2-Ethoxy-3-methylpentane
(vii)Cyclohexylmethanol
(viii)3-Cyclohexylpentan-3-ol
(ix)Cyclopent-3-en-1-ol
(x)3-Chloromethylpentan-1-ol.
Draw the structures of all isomeric alcohols of molecular formula C5H12O and give their IUPAC names. (ii)Classify the isomers of alcohols in question 11.3(i)as primary, secondary and tertiary alcohols.
Explain why propanol has a higher boiling point than that of the hydrocarbon, butane.
Alcohols are comparatively more soluble in water than hydrocarbons of comparable molecular masses. Explain this fact.