To solve this question, let's analyze the assertion and reason provided.
Assertion (A):
All naturally occurring \(\alpha\)-amino acids except glycine are optically active.
Reason (R):
Most naturally occurring amino acids have L-configuration.
1. Optically Active Amino Acids:
Optical activity in amino acids arises from the presence of a chiral center at the \(\alpha\)-carbon (the carbon attached to the amino group, carboxyl group, and side chain). For an amino acid to be optically active, the \(\alpha\)-carbon must not be superimposable on its mirror image (i.e., it must be a chiral center).
2. Glycine and Optical Activity:
Glycine (NH2CH2COOH) is the only naturally occurring \(\alpha\)-amino acid that is not optically active. This is because its \(\alpha\)-carbon is not chiral (it is attached to two hydrogen atoms, making it achiral). Therefore, the assertion that all naturally occurring \(\alpha\)-amino acids except glycine are optically active is correct.
3. The L-Configuration of Amino Acids:
Most naturally occurring amino acids have the L-configuration at the chiral \(\alpha\)-carbon. The L-configuration is the stereochemical form found in proteins. However, the L-configuration does not directly determine optical activity; it is the presence of the chiral center that does.
4. Evaluation of Reason (R):
The reason is true, as most naturally occurring amino acids indeed have the L-configuration. However, the reason does not explain why amino acids are optically active. The optical activity arises from the chiral nature of the amino acid, not just its configuration.
5. Conclusion:
The assertion is correct, but the reason, while true, does not explain the optical activity. Therefore, the assertion is true, but the reason is not fully explanatory.
Final Answer:
The correct option is that the assertion is true, but the reason is false.
Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.
(i) (CH3 )2CHNH2 (ii) CH3 (CH2 )2NH2 (iii) CH3NHCH(CH3 )2
(iv) (CH3 )3CNH2 (v) C6H5NHCH3 (vi) (CH3CH2 )2NCH3 (vii) m–BrC6H4NH2
Give one chemical test to distinguish between the following pairs of compounds.
(i) Methylamine and dimethylamine
(ii) Secondary and tertiary amines
(iii) Ethylamine and aniline
(iv) Aniline and benzylamine
(v) Aniline and N-methylaniline
Account for the following:
(i) pKb of aniline is more than that of methylamine.
(ii) Ethylamine is soluble in water whereas aniline is not.
(iii) Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
(iv) Although amino group is o– and p– directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
(v) Aniline does not undergo Friedel-Crafts reaction.
(vi) Diazonium salts of aromatic amines are more stable than those of aliphatic amines. (vii) Gabriel phthalimide synthesis is preferred for synthesising primary amines.