Arrange the following complexes in the increasing order of conductivity of their solution:
\[
[\text{Cr(NH}_3\text{)}_5\text{Cl}] \text{Cl}_2, \, [\text{Cr(NH}_3\text{)}_3\text{Cl}_3], \, [\text{Cr(NH}_3\text{)}_6\text{Cl}_3]
\]
Solution and Explanation
The conductivity of a compound in solution depends on the number of ions it dissociates into. The greater the number of ions released when the compound dissociates, the higher the conductivity of the solution.
- [Cr(NH3)5Cl]Cl2 dissociates into 2 ions: one of the ions is [Cr(NH3)5Cl] and the other is Cl-.
- [Cr(NH3)3Cl3] dissociates into 4 ions: [Cr(NH3)3Cl3] dissociates into 1 ion of [Cr(NH3)3Cl3] and 3 ions of Cl-.
- [Cr(NH3)6Cl3] dissociates into 6 ions: [Cr(NH3)6Cl3] dissociates into 1 ion of [Cr(NH3)6Cl3] and 3 ions of Cl-.
Order of conductivity:
Since conductivity increases with the number of ions dissociated, the order of conductivity based on the dissociation into ions is:
[Cr(NH3)3Cl3] < [Cr(NH3)5Cl]Cl2 < [Cr(NH3)6Cl3]
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